7x^2+3=10x

Solution for 7x^2+3=10x equation:

7x^2+3=10x

We move all terms to the left:

7x^2+3-(10x)=0

a = 7; b = -10; c = +3;
Δ = b2-4ac
Δ = -102-4·7·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4}{2*7}=\frac{6}{14}
=3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4}{2*7}=\frac{14}{14}
=1
$